Thursday 28 July 2016

Assessment task: Use side or edge lengths to find the perimeters and areas of rectangles, parallelograms, and triangles.

 Use side or edge lengths to find the perimeters and areas of rectangles, parallelograms, and triangles.

Problem 1.



  • So basically the gardeners have 36 slabs to make a rest area in the middle of a lawn.
  • To make it easy to mow they want the area around the slabs (the perimeter) to be a rectangular shape.
  • They want the least space possible around the slabs.
What I have to answer: What arrangement of the tiles gives the smallest possible perimeter? Can you explain why this happens?

Answer: Probably 4 (base) x 8 (height) Or the other way round. Other ways are 10 by 2, 6 be 6 and 1, 11, I think.

Problem 2.

Question: If the gardeners had 48 tiles, how would they arrange them?

Answer: 6 (base) x 8 (height). I don't know if this is the answer but I have checked twice and am sure.

Problem 3.

Someone has a garden that measures 30 by 20. She wants to fertilise her garden. Each bag covers approximately 200 metres square. 

Answer: 3 Bags, because 30 x 20 = 600 and the bags cover 200, so 200 x 3 is 600.


















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